Question

answer this question..... please​

Answer 1

Answer:

Step-by-step explanation:

Proof : In triangles AEG & AFG

AE=AF --- E &F are mid point

AGE=AFG ---- using Euclid's

axiom

AG=AG ---common

So by SAS Cong. cretria

Triangle AEG cong. to triangle AFG.

EG=EF cpct

2) AGE=AGF

AGE+AGF=180 degree--- L.P.

2AGE=180

AGE=AFG=90

Hence proved

Answer 2

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