Math, asked by parshuparekh15paijat, 10 months ago

Answer this question please

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Answered by Anonymous
4

ANSWER

WE KNOW

DIVIDEND = QUOTIENT × (2X-1) + Remainder

DIVIDEND = QUOTIENT × (2X-1) + REMAINDER

SINCE (2X-1) IS A FACTOR SO IT COMPLETELY DIVIDE THE POLYNOMIAL AND LEAVES REMAINDER 0

DIVIDEND = QUOTIENT (2X-1)

PUT X = 1/2

DIVIDEND = 0

we get value of m

IN SECO D QUESTION AGAIN USE THIS RELATION

but here (x-a) is not a factor so here remainder is not 0

now put x = a

we get remainder = a^3-a^2+6a

mark me as brainliest

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