Answer this question please
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ANSWER
WE KNOW
DIVIDEND = QUOTIENT × (2X-1) + Remainder
DIVIDEND = QUOTIENT × (2X-1) + REMAINDER
SINCE (2X-1) IS A FACTOR SO IT COMPLETELY DIVIDE THE POLYNOMIAL AND LEAVES REMAINDER 0
DIVIDEND = QUOTIENT (2X-1)
PUT X = 1/2
DIVIDEND = 0
we get value of m
IN SECO D QUESTION AGAIN USE THIS RELATION
but here (x-a) is not a factor so here remainder is not 0
now put x = a
we get remainder = a^3-a^2+6a
mark me as brainliest
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