Physics, asked by vaishnavi7211, 8 months ago

answer this question.
please​

Attachments:

Answers

Answered by Anonymous
2

Answer:

Since acceleration is a velocity change over a time, the units on acceleration are velocity units divided by time units - thus (m/s)/s or (mi/hr)/s. The (m/s)/s unit can be mathematically simplified to m/s2.

Hope it's helpful buddy and Mark me as brainlist

Answered by Mysterioushine
13

 \huge {\underline {\underline { \pink{ \sf{Answer : - }}}}}

 \sf \: (i) \:  \large {\underline {\blue {\sf{acceleration : - }}}}

Acceleration is defined as the rate of change in velocity. Acceleration is a vector quantity hence it has both magnitude and direction. Acceleration is given by ,

 \large \underline  {\boxed{ \bigstar {\red {\sf{ \: a =  \frac{v - u}{t}  =  \frac{ \Delta  v}{ \Delta  t}   =  \frac{dv}{dt} }}}}}

 \sf (ii) \:  \large {\underline {\orange {\sf{units \: of \: Acceleration : -  }}}}

◉ SI unit of acceleration.

  • SI unit of velocity = m/s
  • SI unit of time = s

Since acceleration is defined as dv/dt.

 \implies \sf \:SI \: unit \: of \: acceleration =  \frac{SI \: unit \: of \:velocity }{SI\: unit \: of \: time}  \\  \\  \implies \sf \:SI \: unit \: of \: acceleration =  \frac{m {s}^{ - 1} }{s}  \\  \\  \implies \sf \: SI \: unit \: of \: acceleration \:  = m {s}^{ - 1}  \times  {s}^{ - 1}

 \large  {\underline{\bold {\boxed {\bigstar {\red {\sf \: { {a}^{m}  \times  {a}^{n}  =  {a}^{m + n} }}}}}}}

 \implies \sf \: SI \: unit \: of \: acceleration = m {s}^{ - 1 + ( - 1)}  \\  \\  \implies {\underline {\bold {\boxed {\blue {\sf{ SI\: unit \: of \: acceleration = m {s}^{ - 2} }}}}}}

◉ CGS unit of acceleration

 \implies  \sf \: CGS \: unit \: of \: acceleration =  \frac{CGS \: unit \: of \: acceleration}{CGS \: unit \: of \: time}  \\  \\  \implies \sf \: CGS \: unit \: of \: acceleration =  \frac{cm {s}^{ - 1} }{s}  \\  \\  \implies \sf \: CGS \: unit \: of \: acceleration = cm {s}^{ - 1}  \times  {s}^{ - 1}  \\  \\  \implies \sf \:CGS \: unit \: of \: acceleration = cm {s}^{ - 1 + ( - 1)}   \\  \\  \implies {\underline {\bold {\boxed {\blue {\sf {\: CGS \: unit \: of \: acceleration = cm {s}^{ - 2} }}}}}}

∴ The SI unit of acceleration is m/s²

CGS unit of acceleration is cm/s²

Similar questions