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Given the length of a cuboidal tank = 30cm.
Given breadth of a cuboidal tank = 20cm.
Given the height of a cuboidal tank = 20cm.
We know that volume of a cuboidal tank = l * b * h
= 30 * 20 * 20
= 12000cm^3.
Given, the tank is placed on a horizontal table and it is 3-Quarters full of Water.
The height of the water = 3/4 * 20
= 15cm.
Now,
Area of the tank which is in contact with water = lb + 2(l + b) * h
= 30 * 20 + 2(30 + 20) * 15
= 600 + 100 * 15
= 2100cm^2.
Therefore the total area of the tank in contact with water = 2100cm^2.
Hope this helps!
Given breadth of a cuboidal tank = 20cm.
Given the height of a cuboidal tank = 20cm.
We know that volume of a cuboidal tank = l * b * h
= 30 * 20 * 20
= 12000cm^3.
Given, the tank is placed on a horizontal table and it is 3-Quarters full of Water.
The height of the water = 3/4 * 20
= 15cm.
Now,
Area of the tank which is in contact with water = lb + 2(l + b) * h
= 30 * 20 + 2(30 + 20) * 15
= 600 + 100 * 15
= 2100cm^2.
Therefore the total area of the tank in contact with water = 2100cm^2.
Hope this helps!
KartikeyJ3:
answer is correct
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