English, asked by aryash7318, 8 months ago

Answer this question please. ​

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Answers

Answered by Sakhtlondi
1

\huge \mathsf{\orange {\underline {\purple {\underline { Required \ answer \ ♡ \  :- }}}}}

Given{ Radius of cone=2cm

⠀⠀⠀⠀ Slant height of cone = 6cm

To find: Curved Surface Area of cone?

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀

\setlength{\unitlength}{1.6mm}\begin{picture}(5,5)\thicklines\put(0,0){\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\put(-0.5,-1){\line(1,2){13}}\put(25.5,-1){\line(-1,2){13}}\multiput(12.5,-1)(2,0){7}{\line(1,0){1}}\multiput(12.5,-1)(0,4){7}{\line(0,1){2}}\put(16,1.6){\sf{2 cm}}\put(22,10){\sf{6 cm}}\end{picture}

⠀⠀⠀

\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\\end{gathered}

\begin{gathered}\star\;{\boxed{\sf{\pink{Curved\:surface\:area_{\;(cone)} = \pi rl}}}}\\ \\\end{gathered}

where,

r = radius = 2 cm

l = Slant height = 6 cm

⠀⠀⠀

\begin{gathered}\dag\;{\underline{\frak{Putting\:values\:in\:formula,}}}\\ \\\end{gathered}

\begin{gathered}:\implies\sf CSA_{\;(cone)} = \pi \times 2 \times 6\\ \\\end{gathered}

\begin{gathered}:\implies\sf CSA_{\;(cone)} = \pi \times 12\\ \\\end{gathered}

\begin{gathered}:\implies{\underline{\boxed{\frak{\purple{CSA_{\;(cone)} = 12 \pi cm^2 }}}}}\;\bigstar\\ \\\end{gathered}

\therefore\:{\underline{\sf{Curved\:surface\: area\:of\:cone\:is\: \bf{12 \pi\:or\: 37.714\:cm^2}.}}}

Answered by ItzDazzingBoy
3

Answer:

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