Question

answer this question please

Answer 1

Answer:

$\frac{1}{ log_{a}(abc) } + \frac{1}{ log_{b}(abc) } + \frac{1}{ log_{c}(abc) } = 1$

Step-by-step explanation:

$\frac{1}{ log_{a}(abc) } + \frac{1}{ log_{b}(abc) } + \frac{1}{ log_{c}(abc) } = \frac{ log(a) }{ log(abc) } + \frac{ log(b) }{ log(abc) } + \frac{ log(c) }{ log(abc) } \\ \\ = \frac{ log(a) + log(b) + log(c) }{ log(abc) } \\ \\ = \frac{log(abc)}{ log(abc) } \\ \\ = 1 \: \: (answer)$