Question

Answer this question Please​

Answer 1

Answer:

LetP(x)=x2-x-1

since à and ß are the zeroes of P(x)

so, à+ß=-b/a=-(-1)/1=1

and à.ß =c/a=-1/1=-1

Now, à^6ß^4+à^4ß^6=à4.ß4(à^2+ß^2)

= à^4ß4[(à+ß)^2-2à.ß ]

=1^4×(-1)^4[(1)^2-2×1×(-1)]

=1×1(1+2)

=1×3

= 3

Step-by-step explanation:

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