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Area of triangleABC= 1/2×22×3
=33sq.cm
Area of triangleADC=1/2×22×3
=33sq.cm
so, area of quadrilateral ABCD=33+33
=66sq.cm
So, the answer is 66sq.cm.
=33sq.cm
Area of triangleADC=1/2×22×3
=33sq.cm
so, area of quadrilateral ABCD=33+33
=66sq.cm
So, the answer is 66sq.cm.
KaranGtm123:
thanks for the ans
Kk
kk means???
Okk
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