Math, asked by AasthaShah130, 1 year ago

answer this question please

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Answered by Varun1870
1

(x^a+b)^a-b × (x^b+c)^b-c × (x^c+a)^c-a x^a2-b2 × x^b2-c2 × x^c2-a2 x^a2-b2+b2-c2+c2-a2 x^0 = 1

Answered by Varun1870
0

(x^a+b)^a-b × (x^b+c)^b-c × (x^c+a)^c-a x^a2-b2 × x^b2-c2 × x^c2-a2 x^a2-b2+b2-c2+c2-a2 x^0 = 1

Answered by Varun1870
0

(x^a+b)^a-b × (x^b+c)^b-c × (x^c+a)^c-a x^a2-b2 × x^b2-c2 × x^c2-a2 x^a2-b2+b2-c2+c2-a2 x^0 = 1

Answered by Varun1870
0

(x^a+b)^a-b × (x^b+c)^b-c × (x^c+a)^c-a x^a2-b2 × x^b2-c2 × x^c2-a2 x^a2-b2+b2-c2+c2-a2 x^0 = 1

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