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angle ABC=BCD(ALTERNATE INTERIOR ANGLES)
BCD=40 SO ANGLE C IS 40
ANGLE BAD=ANGLEADC(SAME REASON)
SI ANGLE D IS 50
ANGLR O+ANGLEC+ANGLE D =180
(SUM OF TRIANGLE ANGLE IS 180)
SO ANGLE O IS 90
BY VERTICAL OPPOSITE ANGLE ANGLE O s OPPOSITE WILL BE EQUAL 90
BCD=40 SO ANGLE C IS 40
ANGLE BAD=ANGLEADC(SAME REASON)
SI ANGLE D IS 50
ANGLR O+ANGLEC+ANGLE D =180
(SUM OF TRIANGLE ANGLE IS 180)
SO ANGLE O IS 90
BY VERTICAL OPPOSITE ANGLE ANGLE O s OPPOSITE WILL BE EQUAL 90
dhruvparikh:
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Given: -
AB||CD
Angle A = 50°
angle B = 40°
then,
by angle sum property...
angle A +angle B + Angle AOB = 180°
50°+ 40° + angle AOB = 180°
angle AOB = 180°-90°
angle AOB = 110°
and,
angle AOB = angle COD (vertically opposite angles)
angle COD= 110°
Angle A = angle D
angle D = 50°
angle B= angle C
angle C = 40°
Hence,
the required angle are: -
angle C = 40°
angle D = 50°
angle COD = 110°
angle AOB = 110°
hope this will help uh...
nd plzz mark as brainliest...
AB||CD
Angle A = 50°
angle B = 40°
then,
by angle sum property...
angle A +angle B + Angle AOB = 180°
50°+ 40° + angle AOB = 180°
angle AOB = 180°-90°
angle AOB = 110°
and,
angle AOB = angle COD (vertically opposite angles)
angle COD= 110°
Angle A = angle D
angle D = 50°
angle B= angle C
angle C = 40°
Hence,
the required angle are: -
angle C = 40°
angle D = 50°
angle COD = 110°
angle AOB = 110°
hope this will help uh...
nd plzz mark as brainliest...
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