Question

answer this question please
if any want to give angle between the forces please answer it as well.​

Answer 1

Answer:

Using Parallelogram law of vector addition,

       R²=A²+B²+2ABcos∅

       20²=(20√3)²+B²+2(20√3)Bcos30

      400=1200+B²+40√3B√3/2

      400=1200+B²+60B

         0=800+B²+60B

On solving the quadratic equation we get,

                 B=-20 N or -40 N

    tan∅=Bsin∅/A+Bcos∅

            =-20sin30/20√3-20cos30

           =-10/20√3-10√3

           =-10/10√3

    tan∅=-1/√3

    ∴∅=30°