answer this question please
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3x2-2x-1= 0
dividing 3 by whole equation
x2-2/3x-1/3= 0
adding and subtracting the half of thecoefficiet of x
x2-2/3x-1/3+(1/3)2-(1/3)2=0
(x-1/3)2-1/3-1/9=0
(x-1/3)2-(1/3+1/9)=0
(x-1/3)2-(4/9)= 0
(x-1/3)2= 4/9
take sq.root both side
(x-1/3)= +_2/3
x = 1/3+_2/3
x = 1/3+2/3. and x = 1/3-2/3
x = 1 and x = -1/3
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