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Answer:
(a) sum of all angle of triangle=180°
In ∆PQR
angle QPR=50°
angle PRQ=X
angle RQP=X
SO
angle QPR + angle PRQ + angle RQP = 180°
50°+X+X=180°
X+X=180°-50°
2X=130°
X=130°÷2
X=65°
AND THIS IS YOUR ANSWER
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