Question

answer this question please please yaar​

Answer 1

Answer:

a= 10 m/s^2

t=0.5 sec

u= 0

1) now, by using first law of motion.

v = u+at

v= 0+10*0.5

v= 5 m/s

2) avg speed = distance travelled/ time

by second law,

s = ut+ 1/2 at^2

s= 1/2*10*0.5*0.5

s= 5*0.5*0.5

s= 1.25 m

hence, avg speed = 1.25/0.5= 2.5.

3) height of the ledge would be equal to the distance travelled.

so, hence the height = 1.25 m

hope it helps...

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Answer 2

Explanation:

picture enot clearly ????