answer this question pls
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Answer:
Ed half of bc and draw imagination line touching to point a it will parallel to de
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Given:
E & D are midpoints of AB and AC
BC=10 cm
Answer:
Since E and D are midpoints, ED || BC
That gives us AD/AB = AE/AC (By Basic Proportionality theorem). {1}
Also, angle DAE = angle BAC {2}
From{1}and{2}:
Triangle ABC ~ Triangle DBE(SAS)
Therefore AD/AB = DE/BC (Corresponding parts of similar triangles)
Since D is the midpoint of AB:
AD/AB=1/2
Which means DE/BC = 1/2
DE/10 = 1/2
That gives us DE = 5 cm
Therefore,DE = 5 cm.
It looks longer than it actually is;it’ll be a walk in the park for you once you get a grasp of the concept.
Mark me as brainliest! Have a nice day.
E & D are midpoints of AB and AC
BC=10 cm
Answer:
Since E and D are midpoints, ED || BC
That gives us AD/AB = AE/AC (By Basic Proportionality theorem). {1}
Also, angle DAE = angle BAC {2}
From{1}and{2}:
Triangle ABC ~ Triangle DBE(SAS)
Therefore AD/AB = DE/BC (Corresponding parts of similar triangles)
Since D is the midpoint of AB:
AD/AB=1/2
Which means DE/BC = 1/2
DE/10 = 1/2
That gives us DE = 5 cm
Therefore,DE = 5 cm.
It looks longer than it actually is;it’ll be a walk in the park for you once you get a grasp of the concept.
Mark me as brainliest! Have a nice day.
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