Math, asked by deladela17678, 13 days ago

Answer this question pls

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Answers

Answered by MKrulesAT9
1

Answer:

cb=41

Step-by-step explanation:

by pythagoras theorem

9 (square )+40 (square )=1681

under root of 1681 =41

ans =41

Answered by Anonymous
31

Given:

  • CA = 9m
  • AB = 40m

To Find:

  • The measure of the side CB

Solution:

➤ Here, we have said that it's a right angled triangle and been provided with the measurements of 2 of its sides CA and AB respectively. Now, we're asked to find its third side CB by using suitable properties of triangles or appropriate theorems

 {\rm{ \underline{ \underline{ \red{Pythagoras  \: therom : }}}}}

✦Pythagoras therom is a theorem which is only applicable for right - angled triangles where, it states that the sum of squares of both the sides is equal to the square of its hypotenuse.

{ \red{ \sf{Formula : }}}

 \rm \: (Hypotenuse) {}^{2}  =  {(Base)}^{2}  +  {(Side)}^{2}

{ \red{ \sf{Here : }}}

↦ CA = Side

↦ AB = Base

↦ CB = Hypotenuse

{ \underline{ \underline{ \red{ \rm{Squaring \:  sides \: we \: get : }}}}}

 \rm \:  {(CB)}^{2}  =  {(AB)}^{2}  +  {(CA)}^{2}  \\  \\\rm \:  {(CB)}^{2} =  {( 9m)}^{2}  +  {(40m)}^{2}  \\  \\ \rm {(CB)}^{2} = 81 {m}^{2}  + 1600 {m}^{2}  \\  \\ \rm {(CB)}^{2} = 1681 {m}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \rm {(CB)}^{2} =  \sqrt{1681 {m}^{2} }  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \rm \: {(CB)}^{2} =  {\red{ \underline{ \boxed{ \sf{41m}}} \star}} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

{ \red{ \sf{Hence : }}}

❂ The measure of the side CB is 41m

{ \underline{ \underline{ \rm{ \red{Verification : }}}}}

We know that a triangle is formed only when the sum of two sides is more than the third side . Here (40 + 9) > 41 . This is means this combination is correct. Even if CB is Hypotenuse its the longest side which is proved as CB > 9,40

{ \underline{ \underline{ \rm{ \red{More  \: to \:  know : }}}}}

✪ Heron's Therom ✪ 

◕Heron's formula, named after Hero of Alexandria, which gives the area of a triangle when the length of all three sides are known.

 \rm \:  \sqrt{S (S  - A) (S - B)( S - C)}

Where,

  • S Denotes Semiperimeter
  • A,B,C are the Sides respectively

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