answer this question Pls.....
Attachments:
Answers
Answered by
1
HEY BUDDY...!!!
HERE'S THE ANSWER...
_______________________
⏺️ We know resistance
=> R = p l / A
⏺️ Where p is resistivity of material , l length of material , A is area of crossection or thickness
⏺️ We also know resistance of Manganin is very high that resistance of copper
⏺️From above statements we can conclude
=> Rc ( resistance of copper )
=> Rc = pc l / A1_______( 1 )
=> pc ( resistivity of copper )
⏺️Now
=> Rm = pm l / A2 ________( 2 )
Now dividing both eqn
=> Rm = Rc ( given )
=> pm / A2 = pc / A1
=> pm >> pc
So A1 > A2
⏺️ Hence copper is more thick
HOPE HELPED..
GOOD MORNING
:-)
HERE'S THE ANSWER...
_______________________
⏺️ We know resistance
=> R = p l / A
⏺️ Where p is resistivity of material , l length of material , A is area of crossection or thickness
⏺️ We also know resistance of Manganin is very high that resistance of copper
⏺️From above statements we can conclude
=> Rc ( resistance of copper )
=> Rc = pc l / A1_______( 1 )
=> pc ( resistivity of copper )
⏺️Now
=> Rm = pm l / A2 ________( 2 )
Now dividing both eqn
=> Rm = Rc ( given )
=> pm / A2 = pc / A1
=> pm >> pc
So A1 > A2
⏺️ Hence copper is more thick
HOPE HELPED..
GOOD MORNING
:-)
singhpinki195:
thanks
Similar questions