answer this question pls pls pls pls pls pls pls ticked ones please please please help
Answers
Q) The maximum number of students among then 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils is ?
------------------
Answer :-
Given :-
- Number of pens - 1001
- Number of pencils - 910
To Find :-
Maximum no. of students among who pencils and pens can be distributed equally.
Solution :-
As we are supposed to find the maximum no. of students,
we will find the highest common factors ( HCF ) of both pens and pencils,
910 = 2, 5, 7 and 13 are the factors.
1001 = 7, 11, and 13 are the factors.
As we can see, the common factors are 7 and 13,
The HCF of 910 and 1001 is 7 x 13 = 91
.·. The maximum number of students are a) 91.
----------------
Q) The greatest number which can divide 1356 and 2764, leaving the same remainder 12 in each case is ?
----------------
Answer :-
Given :-
- Two numbers :-
- 1356 and
- 2764
To Find :-
Greatest number which can divide them, leaving remainder 12.
Solution :-
To find the greatest number, we will subtract 12, and find the HCF.
1356 - 12 = 1344
2764 - 12 = 2752
Now,
1344 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7
2752 = 2 × 2 × 2 × 2 × 2 × 2 × 43
Common prime factors are, 2 × 2 × 2 × 2 × 2 × 2
= 64.
.·. The greatest number is a) 64.
Answer:
→ 2(x − 1) + 5(x − 2) = 5x
→ 2x - 2 + 5x - 10 = 5x
→ 7x - 12 = 5x
→ 7x - 5x = 12
→ 2x = 12
→ x = 12/2
→ x = 6