Question

ANSWER THIS QUESTION PLS URGENT​

Answer 1

$\huge\mathtt\pink{♡Answer♡}$

In △ABD,

∠ABD+∠BDA+∠DAB=180°

by angle sum property

⇒∠DAB=180°−(∠ABD+∠BDA)

⇒∠DAB=180°−(70° +30°)

⇒∠DAB=180° −100°

=80°

∠BAD and ∠BCD are supplementary angles

∴∠BCD=180° −∠BAD=180° −80°

=100° [Ans].

hope it helps ✅✅✅

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Answer 2

Answer:

answer is 35

Step-by-step explanation:

65 - 30