Math, asked by tshantha86, 11 months ago

answer this question plse.....​

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Answered by Anonymous
1

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(a-b)x²+(b+c)x+(c-a) =0

determinent = 0

(b-c) ²-4(a-b) (c-a) = 0

b²+c²-2bc -4ac+4a²+4bc-4ab=0

b²+c²+ (-2a) ²+2bc+2c(-2a) +2(-2a) b= 0

(b²+c²-2a²) =0

(b+c-2a) ²=0

b+c=2a

Answered by harsh260055
0

Answer:

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