Question

answer this question plss​

Answer 1

Answer:

let the width be x m , then l = 6-x

Now A/q , l*w = area

x*6-x=20

x²- 6x = 20

x² - 6x - 20 = 0

it's a quadratic equation

where a= 1 , b = -6 and c = -20

so , applying the formula

-b±√b²-4ac/2a

-(-6)±√-6²-4*1*-20

6±√116/2

6±2√29/2

2(3±√29)/2

3+√29 and 3 -√29

2nd question :-

let width be x m and l = x+4 m

area = w*l

13 = x*x+4

13 = x² + 4x

x² + 4x - 13 = 0

now solve ot by applying the formula

thanq