Question

answer this question plz​

Answer 1

$\LARGE{\underline{\sf{\blue{Solution:}}}}$

Here we are given with area of the triangle and sum of the squares of the perpendicular sides which we have to consider to be x and y metres.

Provided:

• Area of the triangle = 24 cm²
• Sum of their squares = 196 cm²

We have to find the value of x + y, x - y and length of all the sides of the triangle.

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Area of the triangle is given by:

• 1/2 × Perpendicular × Base

Plugging the given values:

➝ 1/2 * xy = 24 cm²

➝ xy = 48 ----------(1)

Now, Sum of their squares is 196 cm²

➝ x² + y² = 196 -----------(2)

1️⃣ We have to find x + y

It can be written as,

➝ √(x + y)²

➝ √x² + y² + 2xy

Plugging the given values,

➝ √196 + 96

➝ √292 cm

➝ 17.09 cm (Approx.)

2️⃣ We have to find x - y

It can be written as,

➝ √(x - y)²

➝ √x² + y² - 2xy

Plugging the given values,

➝ √196 - 96

➝ √100 cm

➝ 10 cm (Approx.)

3️⃣ From (1) and (2), We will get

• x = 13.55 cm
• y = 3.54 cm

By using Pythagoras theoram,

The hypotenuse is 14.004 cm

And we are done !!

Answer 2

Answer:

idk

Step-by-step explanation:

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