answer this question plz
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Answer:
cotθ+tanθ=cosecθsecθ
(cosθ/sinθ)+(sinθ/cosθ) =cosecθsecθ
(cos²θ+sin²θ)/sinθcosθ=1/sinθ×1/cosθ
1/sinθcosθ=1/sinθcosθ
LHS=RHS
Hence proved
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to proove
cotø+tanø= cosec ø +secø
by L.H.S side
COTØ+SINØ = COSØ/SINØ+SINØ/COSØ
CotØ +TanØ=Cos²Ø + Sin²Ø/SinØ•CosØ
(cos²Ø+sin²Ø=1)
CotØ+TanØ=1/CosØ•SinØ
=Cosec Ø•sec Ø
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