Math, asked by janakrajsoni, 1 year ago

answer this question plz

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Answered by ADARSH9999
3
for proving it we have to put value of x in polynomial ie
(1)^2-1
1-1
0

and here we can say that 1 is factor of first polynomial

and for second 1-1
0 and hence it also leaves remainder zero


if you are satisfied then plzz mark me as brainliest

ADARSH9999: and plzz ask your question correct and in english
janakrajsoni: prove that function f(x) is not differentiable function on x=1
ADARSH9999: f (x) is not function it is given for polynomial
ADARSH9999: of variable x and here we can put the value of x to find x-1 is factor of given polynomial or not
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