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Answer:Solution:Explanation:search-icon-headerSearch for questions & chapterssearch-icon-imageClass 12>>Physics>>Ray Optics and Optical Instruments>>Combination of Mirror and Lenses>>An equiconvex lens is cut into two halveQuestionBookmarkAn equiconvex lens is cut into two halves a long (i) XOX and (ii) YOY as shown in the figure let f.f ′ ,f ′′ be the focal lengths of the complete lens of each half in case (i) and of each half in case (ii) respectively Choose the correct statement from the following :642449expand HardSolutionverifiedVerified by TopprCorrect option is C)Initially the focal length of equicontex lens is f1 =(μ−1)( R 1 1 − R 2 1 ) ...(i)f1 =(μ−1)( R 11 −−R1 )= R2(μ−1)Case IWhen lens is cut along XOX, then each half id again equiconvex with R 1=+R,R 2=−RThus, f1=(μ−1)[ R1− −(R)1 ]=(μ−1) R2 = f ′1Case II When lens is cut along XOY, then each half becomes plano-convex with R 1=R,R 2 =∞Thus f1 =(μ−1)( R 11 −R 21 ) =( mRμ−1)= 2f1Hence f=f,f"=2fI
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