Math, asked by trojan123, 1 year ago

answer this question plz fast

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Answered by siddhartharao77
5
Let the total amount of money he left = x.

Given that he left 25% of his money to his mother.

25x/100  ------- (1)


Given that he left 55% to his daughter.

55x/100  ------ (2)

Given that the amount he left to his brother = 9000 ----- (3).


On solving (1),(2),(3), we get

25x/100 + 55x/100 + 9000 = x

x/4 + 11x/20 + 9000 = x

x/4 + 11x/20 = x - 9000

-x/5 = -9000

-x = -45000

x = 45000.


Therefore the money he left = 45000.


The share of his mother = 25/100 * 45000

                                  = 11250.


The Share of his daughter = 55/100 * 45000

                                             = 24750.


Hope this helps!

trojan123: thanks bro
Answered by Anonymous
0
Hey friend!!

Here's ur answer...

================

Let the total income of man = ₹ x

Money given to mother = 25% of x
 \frac{25}{100} \times x \\ \frac{x}{4}
Money with mother = ₹ x/4 -------------(1)

Money given to daughter = 55% of x
 \frac{55}{100} \times x \\ \frac{11x}{20}
Money with daughter = ₹ 11x/20 ---------(2)

Money given to brother = ₹ 9000 --------(3)

Adding (1), (2) & (3)

 \frac{x}{4} + \frac{11x}{20} + 9000 = x \\ \\ \frac{5x + 11x + 180000}{20} = x \\ \\ 16x + 180000 = 20x \\ 4x = 180000 \\ x = \frac{180000}{4} \\ \\ x = 45000

Money with him was ₹ 45000.

Money given to mother = ₹ 11250.

Money given to daughter = ₹24750.

==========================

Hope it may help you...

Thank you :) :)))
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