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Dude, mark me brainliest
let the oxidation number of the atom be 'x'
a) Ca (loses 2 electrons, so, +2)
+2 + 2(+1+x-6) = 0 (over all charge of the compound is zero, and I've multiplied by 2, since there are two entities of HCO₃)
+2 + 2 + 2x - 12 = 0
2x = +8
x= +4
b) sodium loses 1 electron, 2 sodium atoms lose 2 electrons
Oxygen gains 2 electrons, 4 oxygen atoms gain 8 electrons
+2 + x - 8 = 0
x = +6
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Answer:
+4 and +6 respectively
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