Math, asked by Djdevil2006, 10 months ago

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Answered by ojashkumar
0

1) for p(y) = y square - y + 1

-- p(0) = 0 - 0 + 1

   p(0) = 1

-- p(1) = 1 - 1 + 1

   p(1) = 1

-- p(2) = 4 - 2 + 1

   p(1) = 3

2) for p(t) = 2 + t + 2t square - t cube

-- p(0) = 2 + 0 + 0 - 0

   p(0) = 2

-- p(1) = 2 + 1 + 2 - 1

   p(1) = 4

-- p(2) = 2 + 2 + 8 - 8

   p(2) = 4

3) for p(x) = x cube

-- p(0) = 0

   p(0) = 0

-- p(1) = 1

   p(1) = 1

-- p(2) = 8

   p(2) = 8

4) for p(x) = (x - 1) (x + 1)

-- p(0) = (0 - 1) (0 + 1)

   p(0) = 0

-- p(1) = (1 - 1) (1 + 1)

   p(1) = 2

-- p(2) = (2 - 1) (2 + 1)

   p(2) = 4

Hope it helps you!

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Answered by THUNDERBOLT007
0

Answer:

1) for p(y) = y square - y + 1

-- p(0) = 0 - 0 + 1

   p(0) = 1

-- p(1) = 1 - 1 + 1

   p(1) = 1

-- p(2) = 4 - 2 + 1

   p(1) = 3

2) for p(t) = 2 + t + 2t square - t cube

-- p(0) = 2 + 0 + 0 - 0

   p(0) = 2

-- p(1) = 2 + 1 + 2 - 1

   p(1) = 4

-- p(2) = 2 + 2 + 8 - 8

   p(2) = 4

3) for p(x) = x cube

-- p(0) = 0

   p(0) = 0

-- p(1) = 1

   p(1) = 1

-- p(2) = 8

   p(2) = 8

4) for p(x) = (x - 1) (x + 1)

-- p(0) = (0 - 1) (0 + 1)

   p(0) = 0

-- p(1) = (1 - 1) (1 + 1)

   p(1) = 2

-- p(2) = (2 - 1) (2 + 1)

   p(2) = 4

Hope it helps you!

Please mark it as brainliest.

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