answer this question plz with explanation
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ekrajnarang:
hold on
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facrorize both the numerator and denominator
the common factors will cancel out and then finally substitute the value of x
the common factors will cancel out and then finally substitute the value of x
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Lt x->2 (7x^2 - 11x - 6)/(3x^2 - x - 10)
(7x^2 - 14x + 3x - 6)/( 3x^2 - 6x + 5x - 10)
{(7x + 3)(x - 2)}/{(3x + 5)(x - 2)
(7x + 3)/(3x + 5)
17/13
(7x^2 - 14x + 3x - 6)/( 3x^2 - 6x + 5x - 10)
{(7x + 3)(x - 2)}/{(3x + 5)(x - 2)
(7x + 3)/(3x + 5)
17/13
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