Question

answer this question plz...
within few minutes ... plz​

Answer 1

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Answer 2

Answer:

Let the given APs AP1 & AP2

For AP1

a1 = -1, n1 = 4 , d1 = d

Tn(1) = a1 + (n1 - 1)d

T4 (1) = -1 + (4-1)d

T4(1) = 3d-1 ........... (1)

For AP2

a2 = -8 n2 = 4 , d2 = d

Tn(2) = -8 + (4-1)d

T4(2) = 3d -8 ........... (2)

Subtract (2) from (1)

T4 (1) - T4 (2) = (3d-1)-(3d-8)

T4(2) - T4(1) = 3d-1-3d+8 = 7

So the difference b/w 4th term is 7

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