Question

answer this question plzz​

Answer 1

Answer:

WE ARE USING LAWS OF EXPONENTS

Step-by-step explanation:

Q1. ACC. TO LAWS OF EXPONENTS

5^10÷5^8= 5^10-8

SO 5^10÷5^8=5^2

NOW 5^2=1/5^n

NOW,SHIFT THE 5 AT R.H.S TO L.H.S

THEREFORE IT BECOMES 5×5^2=1^n

1. ACC TO LAWS OF EXPONENTS - WHEN BASES#5 ARE SAME THEN DEGREES ADD

SO 5×5^2= 5^3

NOW, 5^3=1^n

TO SEPARATE N SHIFT 1 TO L.H.S

THEN 5^3×1=N

N= 5^3= 125

Q2. HERE U WILL SEE THAT NUMERICS AT L.H.S ARE SAME ,POWER IS CHANGE AND THEY ARE IN DIVIDE MEANS

1. ACC TO LAWS OF EXPONENTS WE HAVE TO SUBTRACT POWERS

-2/3^4-3= -2/3^1

NOW THE EQUATION BECOMES-

-2/3^1=-3/2^n

Now, TO FIND N WE HAVE TO SEPARATE IT AND MULTIPLY THE NUMERICS

THEN, N= -2/3×-3/2 NOW, WE KNOW POWERS OF BOTH

ARE SAME MEANS WE WILL MULTIPLY BASES

THAT IS -2/3×3/2=-6/6

= 1/1^1

=-1^1 IS ANSWER

REGARDS@THANKS

BY- @THEVIBHANSHU