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put z = 3 in both polynomials then take them equal then u will get equation in a ... Solve this equation to get value of a ......
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z=3
then A(3)3+4(3)2+3(3)-4=(3)3-4(3)+A
27A+36+9-4=27-12+A
27A+45-4=15+A
27A+41=15+A
27A-A=15-41
26A=-26
A=-1
Hope it helps
then A(3)3+4(3)2+3(3)-4=(3)3-4(3)+A
27A+36+9-4=27-12+A
27A+45-4=15+A
27A+41=15+A
27A-A=15-41
26A=-26
A=-1
Hope it helps
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