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Step-by-step explanation:
in triangle ADB
AB= 25m
BD= 20m(height)
AD=15m (base)
area of triangle= 1/2×base×height
= 1/2×15×20
= 1×15×10 (divided 20 by 2)
= 150sq.m
in triangle BDC
BC=18m
CD=14m (base)
BD=20m (height)
area of triangle= 1/2×base×height
= 1/2×14×20
= 1×14×10 (divided 20 by 2)
= 140sq.m
area of fig ABCD= area if triangle ABD+ area of triangle BCD
= 150+140
= 290sq.m
_______________________________________
do same with fig 2
in triangle ABD
Take AD as height
take AB as base
in triangle BCD
take BD as height
and BC as base
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