Physics, asked by Anonymous, 5 months ago

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Answered by veerkiri007
1

Answer:

1. linear or uniform motion

2. the body is not moving,but time will move.

3. non-uniform.

4. 22.5 m/s.

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Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
15

\underline{\underline{\pink{\huge\sf Answer}}}

Question 1

1) From A to B we see that the slope of the graph gives us a straight line and if it is a straight line then as per our definition "When a body travels equal distances in equal interval then it is said to be in Uniform Motion". And so the body has a uniform speed from A to B.

2) During A to B the body has travelled 5 units but take a look at B to C the distance travelled has not increased,i.e

\sf Speed = \dfrac{Distance}{Time}

\sf Speed = \dfrac{0}{3}

\sf \green{Speed = 0}

\sf \therefore Body is in rest

3) We know that,

»» Uniform Motion = Equal Distances in unequal time [Distance/Time = straight line]

»» Non Uniform Motion = Unequal Distance in equal intervals of time [Distance/Time = Not a straight line]

So here A to B is Uniform, B to C is uniform (0) and C to D is uniform but A to B ≠ B to C ≠ C to A and so A to D represents Non Uniform Motion

4) Average Speed is given by,

\sf \underline{\boxed{\sf Avg \ speed = \dfrac{Total \ Distance}{Total \ Time}}}

  • Total Distance = 7 cm
  • Time = 9 sec

Substituting the values,

\sf Avg \ Speed = \dfrac{Total \ Distance}{Total \ Time}

\sf Avg \ Speed = \dfrac{7}{9}

\sf \red{Avg \ Speed = 0.78 \ cm/s}

Question 2

So here we may see that the distance travelled by the body is equal in equal intervals so it will be a uniform motion,in a uniform motion the D/T graph will be a straight line.

\setlength{\unitlength}{1 cm}\begin{picture}(16,8)\thicklines\put(0.9,9){\tt Y}\put(8.9,0.9){\tt X}\put(0.7,0.5){\sf0}\put(1,1){\circle*{0.1}}\put(1,1){\vector(1,0){7.8}}\put(1,1){\vector(0,1){7.8}}\put(8,0.9){\line(0,1){0.2}}\put(2,0.9){\line(0,1){0.2}}\put(3,0.9){\line(0,1){0.2}}\put(4,0.9){\line(0,1){0.2}}\put(5,0.9){\line(0,1){0.2}}\put(6,0.9){\line(0,1){0.2}}\put(7,0.9){\line(0,1){0.2}}\put(0.9,8){\line(1,0){0.2}}\put(0.9,2){\line(1,0){0.2}}\put(0.9,3){\line(1,0){0.2}}\put(0.9,4){\line(1,0){0.2}}\put(0.9,5){\line(1,0){0.2}}\put(0.9,6){\line(1,0){0.2}}\put(0.9,7){\line(1,0){0.2}}\qbezier(1.09,1)(2,2)(7.8,8)\put(1.9,0.5){\sf3}\put(2.9,0.5){\sf6}\put(3.9,0.5){\sf9}\put(4.8,0.5){\sf12}\put(5.7,0.5){\sf15}\put(6.7,0.5){\sf18}\put(7.8,0.5){\sf20}\put(0.6,1.9){\sf4}\put(0.6,2.9){\sf6}\put(0.6,3.9){\sf8}\put(0.5,4.9){\sf10}\put(0.5,5.9){\sf12}\put(0.5,6.9){\sf14}\put(0.5,7.9){\sf16}\put(3,0.1){\vector(1,0){3.5}}\put(4.3,-0.3){\sf Time(s)}\put(0.1,2){\vector(0,1){3.5}}\put(-0.19,4.6){\sf D}\put(-0.17,4.3){\sf i}\put(-0.17,4){\sf s}\put(-0.17,3.7){\sf t}\put(-0.17,3.4){\sf a}\put(-0.17,3.1){\sf n}\put(-0.17,2.8){\sf c}\put(-0.17,2.5){\sf e}\end{picture}

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