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since CE perpendicular to AB AE=BE
(perpendicular to a chord from centre bisect it)
In Triangle AEC AND BEC
AE = BE
CE=CE
/_CEA =/_CEB
By SAS
triangle are congruent
so AC =BC
in triangle ACB
AC =BC
so it is an isosceles triangle
(perpendicular to a chord from centre bisect it)
In Triangle AEC AND BEC
AE = BE
CE=CE
/_CEA =/_CEB
By SAS
triangle are congruent
so AC =BC
in triangle ACB
AC =BC
so it is an isosceles triangle
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