Answer this question quickly
Attachments:
Answers
Answered by
3
∛{(a^6×b³×c^21)/c^9×a^12}=∛a^(6-12)×b³×c^(21-9) =∛a^(-6)×b³×c^12 =∛{b³×c^12}/a^6 =b×c^4/a^2 ans
Similar questions