Math, asked by sonusinganiya6p9ydt2, 11 months ago

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Answered by jhaanamikaduttp77m4u
3

∛{(a^6×b³×c^21)/c^9×a^12}=∛a^(6-12)×b³×c^(21-9) =∛a^(-6)×b³×c^12 =∛{b³×c^12}/a^6  =b×c^4/a^2 ans

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