answer this question show the steps too
if a=2 and b=3 find
i) (a^b + b^a )^-1
ii) (a^a + b^b)^-1
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1.(2^3+3^2)-1
=(8+9)-1
=17-1
=16
2.(2^2+3^3)-1
=(4+27)-1
=31-1
=30
=(8+9)-1
=17-1
=16
2.(2^2+3^3)-1
=(4+27)-1
=31-1
=30
anindyaavdhi321:
-1 is the whole power of the brackets in both the questions so you don't have to subtract -1 . I think we have to write the reciprocal of 17 and 31
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