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a÷(b+c) = [(-10)÷(1+1)]
=> [-10 ÷2]
=> -5
_____________________
(a÷b) + (a÷c) = [(-10)÷1] + [(-10) ÷ 1]
=> [-10] + [-10]
=> -10 -10
=> -20
-5 ≠ -20
So,
a÷(b+c) ≠ (a÷b) + (a÷c)
i hope this will help you
-by ABHAY
=> [-10 ÷2]
=> -5
_____________________
(a÷b) + (a÷c) = [(-10)÷1] + [(-10) ÷ 1]
=> [-10] + [-10]
=> -10 -10
=> -20
-5 ≠ -20
So,
a÷(b+c) ≠ (a÷b) + (a÷c)
i hope this will help you
-by ABHAY
abhi569:
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