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Answer:
According to the question, we are asked to solve 3x-5=7x+3.
We have been given the equation is 3x-5=7x+3. ---------(1)
We first have to consider the equation (1).
Subtract the whole equation by 3x. We get,
3x-3x-5=7x+3-3x
We know that terms with the same magnitude and opposite signs cancel out. Here, cancelling 3x, we get
-5=7x-3x+3
⇒7x+3−3x=−5
Let us now group all the x terms and simplify.
⇒(7−3)x+3=−5
On further simplification, we get
4x+3=-5
Now, subtract 3 from both the sides of the equation.
⇒4x+3−3=−5−3
We know that terms with the same magnitude and opposite signs cancel out. Here, cancelling 3, we get
4x=-5-3
On further simplification, we get
4x=-8
Now, divide the whole obtained equation by 4.
⇒4x4=−84
We can express the equation as
4x4=−4×24
We find that 4 are common in both the numerator and denominator of both the LHS and RHS.
Let us cancel the common terms.
We get x=-2.
Therefore, the value of x in the equation 3x-5=7x+3 is -2.