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remainder will be equal to zero
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Given Equations :
f(x) = x⁴ + 0x³- 3x² + 0x + 4 and g(x) = x - 2
By remainder theorem, we can make g(x) = 0 and find the value of x.
⟹ x - 2 = 0
\boxed{ \sf{x = 2}}
x=2
Substituting the value of x in f(x),
⟹ f(x) = x⁴ + 0x³ - 3x² + 0x + 4
⟹ f(2) = (2)⁴ + 0(2)³ - 3(2)² + 0(2) + 4
⟹ f(2) = 16 + 0 - 12 + 0 + 4
⟹ f(2) = 8
So by using remainder theorem, we got the remainder as 8.
Let us now verify the result by using actual long division method.
Have a look at the attachment!
After dividing f(x) by g(x), we got :
The Quotient as x³ + 2x² + x + 2
The remainder as 8.
Hence Verified!
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