Question

answer this question
$20 {x}^{2} - 45$

Answer 1

Given that

$= > 20 {x}^{2} - 45 = 0\\ \\ = > 5(4 {x}^{2} - 9) = 0\\ \\ = > 4 {x}^{2} - 9 = 0\\ \\ = > 4 {x}^{2} = 9 \\ \\ = > {x}^{2} = \frac{9}{4} \\ \\ = > x = \frac{3}{2} \: and \: x = - \frac{3}{2}$

⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐

I hope it will help you a lot

thanks

Answer 2

HEY HERE IS YOUR ANSWER BRO☺☺☺☺

${20x}^{2} - 45 \\ \\ 5( {4x}^{2} - 9) \\ \\ 5( ({2x})^{2} - ( {3})^{2} \\ \\ it \: is \: in \: the \: format \: \: {a}^{2} - {b}^{2} \\ we \: have \: to \: factorise \: in \: the \: \\ \: format(a + b) \: (a - b) \\ \\ 5(2x + 3) \: (2x - 3) \: is \: the \: \\ required \: answer \:$

HOPE IT HELPS ☺☺☺☺☺
PLEASE MARK AS BRAINLIEST
#AADI 93