Chemistry, asked by AleXXa, 1 year ago

Answer this question....Thanks❤️❤️​

Attachments:
amritstar: option d
amritstar: △ng = 0 so equilibrium will does not shift
amritstar: but V is decreased, C = moles/ volume. as V is decreased Concentration is increased, so option D
AleXXa: yo

Answers

Answered by harshoraon76
0

If you really want to thank someone for a good answer, then you'll perhaps take the time .... The satisfaction of answering a question is, in itself, thanks enough.

Answered by PSN03
0

its option 2 as

in both the cases the no of  moles gasesous products are same so no change in concentration of either.

AleXXa: nope , its option 4
AleXXa: leave it
AleXXa: edit it, i will mark uh brainliest ^_0
PSN03: i don't like free points
PSN03: but how is it 4th
PSN03: i mean equilibrium will shift to that side which has lesser no of gaseous moles
AleXXa: yeah, for this reactant and product both will increase
PSN03: ohk
AleXXa: qwerty then
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