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amritstar:
option d
△ng = 0 so equilibrium will does not shift
but V is decreased, C = moles/ volume. as V is decreased Concentration is increased, so option D
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its option 2 as
in both the cases the no of moles gasesous products are same so no change in concentration of either.
nope , its option 4
leave it
edit it, i will mark uh brainliest ^_0
i don't like free points
but how is it 4th
i mean equilibrium will shift to that side which has lesser no of gaseous moles
yeah, for this reactant and product both will increase
ohk
qwerty then
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