Question

Answer this question : The number of 3×3 non - singular matrices , with four entries as 1 and all other as 0, is a) 5 b) 6 c) at least 7 d) less than 4 . do not spam .

Answer 1

Answer:

Option - (c)

Step-by-step explanation:

Given that there are four 1's and five 0's.

In this 3 * 3 matrix, no row or column can have three 0's because it becomes singular.

We can avoid this by placing only 1's in the principal diagonal.

$\left[\begin{array}{ccc}1&-&-\\-&1&-\\-&-&1\end{array}\right]$

These 6 blanks will be filled by five 0's and one 1.

So, total number of ways = 6.

Similarly,

$\left[\begin{array}{ccc}-&-&1\\-&1&-\\1&-&-\end{array}\right]$

Here, again the remaining blanks can be occupied by five 0's and one 1.

Total number of ways = 6.  --- > Non singular matrices.

Hence, Number of non-singular matrices = 6 * 6 = 36.

Therefore, there are more than 7 non-singular matrices.

Hope it helps!

Answer 2

Answer:

okay..

Step-by-step explanation:

thnx for ur advice/opinion..

i understand so frm. next time i will never do..

but yr people r Deleting my maths questions

that's why i said..