ANSWER THIS QUESTION!!!
The sum of first 9 terms of an AP is zero and its 7th term is 10 find the sum of the first
23 terms
Answers
Answered by
1
Answer: 805
Step-by-step explanation:
The solution is in the pic. attached.
Attachments:
![](https://hi-static.z-dn.net/files/d83/3088c33e2697c39c4e1e5acaa857b7f2.jpg)
![](https://hi-static.z-dn.net/files/da5/d49abf90337455a494dae46bb20e72cd.jpg)
Answered by
2
The sum of the first 23 terms is 805.
Given:
The sum of first 9 terms=0
7th term=10
To find:
The sum of the first 23 terms
Solution:
Let the first term of the A.P. be a and the common difference be d.
The 7th term=a+(7-1)d
10=a+6d (1)
Similarly, the sum of the first 9 terms=9/2×(2a+(9-1)d)
0=9/2×(2a+8d)
0=2a+8d
0=a+4d (2)
We will subtract (1) and (2).
a+6d-(a+4d)=10-0
a+6d-a-4d=10
2d=10
d=5
Putting d=5 in (2),
0=a+4×5
0=a+20
a= -20
So, the sum of the first 23 terms=23/2×(2a+(23-1)d)
Using the values of a and d,
=23/2×(2(-20)+22×5)
=23/2×(-40+110)
=23/2×70
=23×35
=805
Therefore, the sum of the first 23 terms is 805.
Similar questions