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The sum of first 9 terms of an AP is zero and its 7th term is 10 find the sum of the first
23 terms
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Answer: 805
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The sum of the first 23 terms is 805.
Given:
The sum of first 9 terms=0
7th term=10
To find:
The sum of the first 23 terms
Solution:
Let the first term of the A.P. be a and the common difference be d.
The 7th term=a+(7-1)d
10=a+6d (1)
Similarly, the sum of the first 9 terms=9/2×(2a+(9-1)d)
0=9/2×(2a+8d)
0=2a+8d
0=a+4d (2)
We will subtract (1) and (2).
a+6d-(a+4d)=10-0
a+6d-a-4d=10
2d=10
d=5
Putting d=5 in (2),
0=a+4×5
0=a+20
a= -20
So, the sum of the first 23 terms=23/2×(2a+(23-1)d)
Using the values of a and d,
=23/2×(2(-20)+22×5)
=23/2×(-40+110)
=23/2×70
=23×35
=805
Therefore, the sum of the first 23 terms is 805.
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