Math, asked by darshryan, 1 year ago

*answer this question to get 45 points !!!!!!!!!*

[(64)^(2/3)]-[( 5)]-[(2)^(5])+[(27)^(-2/3])*[(25/9)^(-1/2)]

Answers

Answered by PrincessStargirl
12

Heya!


Here is your answer.



[(64)^(2/3)]-[( 5)]-[(2)^(5])+[(27)^(-2/3])*[(25/9)^(-1/2)]



= 64^2/3-5-2^5+(27^-2/3) ((25/9)^-1/2)



= 16-5-2^5+(27^-2/3)((25/9)^-1/2



= 11-2^5+(27^-2/3)((25/9)^-1/2



= 11-32+(27^-2/3)((25/9)^-1/2



= -21+(27^-2/3)((25/9)^1/2)



= -21+0.111111(29/9)^1/2



= -21+(0.111111)(0.6)



= -21+0.066667



,= -20.933



⭐ Hope it helps ⭐

Answered by ans81
0
HEY MATE HEY MATE HERE IS

 <b>

 =  >( {64 }^{ \frac{2}{3} } ) - (5) - (2 {)}^{5}  + (27 {)}^{ \frac{ - 2}{3}  \times  \frac{(25}{9}  {)}^{ \frac{ - 1}{2} } }

➡️ 1331.65 answer





Hope it will help you

@thanksforquestion

@bebrainly
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