Question

ANSWER THIS QUESTION TO GET A BRAINLIEST(CLASS 9)

Answer 1

EXPLANATION :-

Here the two lawsof exponent be used that is

$( \frac{a}{b} ) {}^{n} = \frac{a {}^{n} }{b {}^{n} }$

$(a {}^{m} ) {}^{n} = a {}^{mn}$

From this If we use all terms get cancelled we get 1

Method - 2

$(\frac{x {}^{a} }{x {}^{b} } ) {}^{c} \times ( \frac{x {}^{b} }{x {}^{c} } ) {}^{a} \times (\frac{x {}^{c} }{x {}^{a} } ) {}^{b}$

$\dfrac{x {}^{ac} }{x {}^{bc} } \times \dfrac{x {}^{ab} }{x {}^{ac} } \times \dfrac{x {}^{bc} }{x { }^{ac} }$

${x^{(ac-bc) \times x^(ab-ac) \times x^(bc-ab)}}$

${x^{ac-bc+ab-ac+bc-ab}}$

${x^0}$

= 1

Hence proved !

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Know more some exponents and laws :-

$a {}^{m} \times a {}^{n} = a {}^{m + n}$

$\dfrac{a {}^{m} }{a {}^{n} } = a {}^{m - n}$

$a {}^{ - n} = \dfrac{1}{a {}^{n} }$

$a {}^{0} = 1$

$( \frac{a}{b} ) {}^{ - n} = ( \frac{b}{a} ) {}^{n}$

Answer 2

Answer:

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