Question

Answer this question:
two solids of right cylinder are 49cm and 35cm high and their base diameters are 16cm and 14cm respectively. both are melted and moulded into a single cylinder, 56cm high. find its base diameter....​

Answer 1

C1=pi*r^2*h
=22/7*49*8*8
=9856cm^3
C2=pi*r^2*h
=22/7*7*7*35
5390cm^3
C3=pi*r^2*h
15246(adding both volumes)=22/7*r^2*56
15246=22/7*56*r^2
15246=22*8*r^2
15246=176*r^2
15246/176=r^2
86.625=r^2
r= root of 86.625
r=9.3cm

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