Math, asked by primaninterrasant, 1 year ago

answer this question when 2 to the power 3 by 2 can be solved as

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Answered by prachistar2000
0

  {2}^{3 \div 2}  \\  =  {2}^{1 + 1 \div 2}   \\  = {2}^{1}  \times  {2}^{1 \div 2}  \\  = 2 \sqrt{2}
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