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answer is zero ?
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lim x→0 (√4+x - 3√8+3x)/ x
put x = 0
this wil give 0/0 form
Now we can solve it using l - hospital rule
lim →0 d/dx (√4+x - 3√8+3x)/d/dx(x)
=> lim x→0 1/2√4+2 - 1/(8+3x)^2/3
Now put x = 0
WE GET
=> 1/2(√4+0) - 1/(8+3(0))^2/3
= 1/2√4 - 1/(8)^2/3
= 1/4 -1/4
=> 0
THUS
lim x→0 (√4+x - 3√8+3x)/ x = 0
put x = 0
this wil give 0/0 form
Now we can solve it using l - hospital rule
lim →0 d/dx (√4+x - 3√8+3x)/d/dx(x)
=> lim x→0 1/2√4+2 - 1/(8+3x)^2/3
Now put x = 0
WE GET
=> 1/2(√4+0) - 1/(8+3(0))^2/3
= 1/2√4 - 1/(8)^2/3
= 1/4 -1/4
=> 0
THUS
lim x→0 (√4+x - 3√8+3x)/ x = 0
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