Physics, asked by Mithunzzz, 9 months ago

answer this question with clear explanation please explain​

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Answered by nirman95
2

Answer:

Lens formula is the formula which relates Focal length of lens (f) , object distance (u) and image distance (v).

Let us consider that an object has been placed at a distance u on the left side of a lens and an image is produced (may be on left side ir on right side of lens depending on situations) , then we can relate the 3 variables as :

 \bigstar \:  \:  \:  \dfrac{1}{f}  =  \dfrac{1}{v}  -  \dfrac{1}{u}

Now following sign convention , since the object is placed on the left side of the lens , it's position will be negative (-u)

 \bigstar \:  \:  \:  \dfrac{1}{f}  =  \dfrac{1}{v}  -  \bigg(\dfrac{1}{ - u}  \bigg)

 \implies \:  \:  \:  \dfrac{1}{f}  =  \dfrac{1}{v}   +  \dfrac{1}{ u}

An important point to note is that :

While putting the value of Object distance in this equation, you have to simply put the value as sign convention has already been used

Answered by raj6174
0

Explanation:

Answer:

Lens formula is the formula which relates Focal length of lens (f) , object distance (u) and image distance (v).

Let us consider that an object has been placed at a distance u on the left side of a lens and an image is produced (may be on left side ir on right side of lens depending on situations) , then we can relate the 3 variables as :

\bigstar \: \: \: \dfrac{1}{f} = \dfrac{1}{v} - \dfrac{1}{u}★

f

1

=

v

1

u

1

Now following sign convention , since the object is placed on the left side of the lens , it's position will be negative (-u)

\bigstar \: \: \: \dfrac{1}{f} = \dfrac{1}{v} - \bigg(\dfrac{1}{ - u} \bigg)★

f

1

=

v

1

−(

−u

1

)

\implies \: \: \: \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{ u}⟹

f

1

=

v

1

+

u

1

An important point to note is that :

While putting the value of Object distance in this equation, you have to simply put the value as sign convention has already been used

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